3 years ago

I plugged this into photo math, but apparently I have to pay to find out how to get the answer. can you guys help me out?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

8 0

Photo math is charging? We don't need it. We factor the difference of two squares.

$\dfrac{5t^2-500}{t+10} = \dfrac{5(t^2- 100)}{t+10} = \dfrac{5(t-10)(t+10)}{t+10} = 5(t-10) = 5t-50$

Answer: 5t-50

You might be interested in

a family buys a car for $20,000. the value of the car decreases about 20% each year. after 6 years, the family decides to sell t

Neporo4naja [7]

No, the car is losing value not gaining it.

7 0

3 years ago

Read 2 more answers

Please help I’m down bad atm

kogti [31]

Answer:

the answer is an-as-1+1;a,=1

5 0

3 years ago

Vladimir is walking down the street at a speed of 4 miles per hour. Write an equation for the distance in miles, d, that Vladimi

zubka84 [21]

Answer:

$d=4t$

Step-by-step explanation:

We have been given that Vladimir is walking down the street at a speed of 4 miles per hour. We are asked to write an for the distance in miles, d, that Vladimir walks over time in hours, t.

We will use rate formula to solve our given problem.

$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

$\text{Distance}=\text{Speed}\times\text{Time}$

Upon substituting our given information in distance equation, we will get:

$d=4\cdot t$

$d=4t$

Therefore, the equation $d=4t$ represents the distance that Vladimir walks over time in hours.

8 0

3 years ago

6+4*(5-7)^2 need answer with worked out problem

Dennis_Churaev [7]

6+4• (5-7)^2
(5-7)^2
-2^2
4
6+4+4
=14

6 0

3 years ago

Last week Rachel power walked 2 3/5 miles per day on each of the seven days during the same week she also jogged 5 3/4 per day o

Korolek [52]

41 and 1/5 miles.

You can get this by multiplying the distances by number of days. Then add the two together.

3 0

3 years ago

I plugged this into photo math, but apparently I have to pay to find out how to get the answer. can you guys help me out?​

I plugged this into photo math, but apparently I have to pay to find out how to get the answer. can you guys help me out?