An example for #1 would be that: 15 is divisible by 3, but not 9. every third multiple of 3, (9, 18, 27,...) is divisible by 9 because 9 is three times the size of 3.
For part two the first number that I thought of is 23.
Answer:
x₁ = -4
x₂ = 3
Step-by-step explanation:
x²+ x + 12 = 0
x = {-1±√((1²)-(4*1*-12))} / (2*1)
x = {-1±√(1+48)} / 2
x = {-1±√49} / 2
x = {-1±7} / 2
x₁ = {-1-7} / 2 = -8/2 = -4
x₂ = {-1+7} / 2 = 6/2 = 3
Check:
x₁
-4² + (-4) - 12 = 0
16 - 4 - 12 = 0
x₂
3² + 3 - 12 = 0
9 + 3 - 12 = 0
Answer:
Part a) Option d
Part b) Option a
Step-by-step explanation:
Part a
if we look at the options given and the data available
Option a) x^4+9
Putting x= 2 we get (2^4) + 9 =25
Putting x= 3 we get (3^4) + 9 =90 but f(x) =125 so not correct option
Option b) (4^x)+9
Putting x= 2 we get (4^2) + 9 =25
Putting x= 3 we get (4^3) + 9 =73 but f(x) =125 so not correct option
Option c) x^5
Putting x= 2 we get (2^5) =32 but f(x) =25 so not correct option
Option d) 5^x
Putting x= 2 we get (5^2) =25
Putting x= 3 we get (5^3) =125
Putting x= 4 we get (5^4) =625
So Option d is correct.
Part (b)
3(2)^3x
can be solved as:
=3(2^3)^x
=3(8)^x
So, correct option is a
The answer to this problem is =<span><span><span><span>−9/</span>10</span>x</span>+<span><span>−85/</span><span>6</span></span></span>
Explanation:
<u><em>First you subtract by -1 both sides of an equation.</em></u>
<u><em>
</em></u>
<u><em>Then, simplify the number.</em></u>
<u><em>34-1=33</em></u>
<u><em>x>33</em></u>
<u><em>Or interval notation 33,∞ </em></u>
<u><em>Final answer: → x>33 and 33,∞</em></u>
<u><em>Hope this helps!</em></u>
<u><em>Thanks!</em></u>
