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natka813 [3]
3 years ago
10

What is the end behavior of f(x)=5x^3-2x+5

Mathematics
2 answers:
VashaNatasha [74]3 years ago
7 0
F ( x) = 5x^3 - 2x + 5

y = 5x ^3 - 2x + 5

LEFT END = RISING &  RIGHT END = RISING 
serg [7]3 years ago
5 0
F(x)  = 5x³-2x+5

The end behavior of a polynomial is the behavior of the graph when:
x→ + ∞  and x → - ∞

when x → + ∞, f(x) → +∞

and when x → - ∞ , f(x) → - ∞

You follow the sign of the greatest exponent , that is 3 (on 5x³)

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Consider the graph of f(x) given below.
tiny-mole [99]

The functions could represent g(x) is B. g(x) = f(x - 5)

<h3>How can the function be determined?</h3>

Using the general equation g(x) =f(x)+ b

The g(x) has intercept of y=-2,

Then the  y-intercept of f(x) is at y=3

If we find the difference between both y-intercepts, we have

( -2 -3) = -5

Then b=-5

Hence, g(x) = f(x - 5) is correct.

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5 0
1 year ago
the rain caused the river to rise a total of 6 2/3 inches. the river was was rising a an average of 2/3 of an inch each hour. ho
Tasya [4]
2 1/2 you divide 6 2/3 by 2/3
8 0
3 years ago
Question 3 (1 point) If the following is a rhombus, find the missing measures. Find PQ. PQ=​
Svetllana [295]

Answer:

Step-by-step explanation:

PQ*PQ=PQ²=(5x+16)²=25x²+160x+256

8 0
2 years ago
Please help as soon as possible Will mark BRAINLIEST!!!!!
omeli [17]

Answer:

Width = 40ft

Step-by-step explanation:

Area of a rectangle = Length x Width

=> 1600 = 40 x W

=> 1600 = 40W

=> 1600/40 = 40W/40

=> 40 = W

So, the width is 40 ft

6 0
2 years ago
Read 2 more answers
On the first 4 exams of his language class, Ishaan got an average score of 82. What does he need on the next exam to have an ove
dangina [55]

Ishaan to have a score of 97 on the next exam have an overall average of 85

What is the mean of exam scores?

The mean of exam scores is the sum of the scores divided by the number of exams taken, more like an average of all scores

Initially, average score on 4 exams is 82

average=total score/number of exams

average score on 4 exams=82

total score =unknown=assume it is

number of exams=4

82=x/4

x=4*82

x=328

In order to have an overall average score of 85, we would sum the total score of 4 exams and the fifth exam and divide by 5 exams

85=(328+y)/5

85*5=328+y

425=328+y

y=425-328

y=97

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8 0
1 year ago
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