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goldfiish [28.3K]
3 years ago
13

What is the square root of 12 plus the square root of 27?

Mathematics
2 answers:
Ghella [55]3 years ago
8 0
Square root of 12 = 3.46
Square root of 27= 5.19
Add together you get 8.65
marysya [2.9K]3 years ago
4 0
93 hope that helped u :)
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In a class no of girls is 11 more than the no of boys .If the total no.of students in the class is 55 how many are girls?
True [87]

Answer: There are 33 girls in the class

Step-by-step explanation:

6 0
3 years ago
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In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are
Vitek1552 [10]
1. Let's call the number of carter school: "x" and "y" the number of alternative school.  Then, you have that:

 - T<span>he number of charter schools is 4 less than twice the number of alternative schools.
</span> - T<span>here are 48 charter schools in the country.

 2. So, you have:

 x=2y-4  (i)

 x=48  (ii)

 3. Then, when you substitute x=48 into the equation (i), you obtain:
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 x=2y-4
<span> 48=2y-4

 4. Now, you must clear "y, as below:

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6 0
3 years ago
Which expression is equivalent to 4(x+2)?
Alex73 [517]
Hello!

You can expand the 4

4x + 8

the answer is 4x + 8

Hope this helps!
5 0
3 years ago
yesterday Josh sold some boxes of greeting cards. today he sold seven boxes .if he sold 25 boxes in all , how many did he sell
Galina-37 [17]

If he sold 25 boxes in all and he sold 7 today then he would of sold 25 - 7 boxes yesterday. Josh sold 18 boxes yesterday.

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Yesterday = 18

Total = 25

7 + x = 25, when x = Yesterdays sold boxes.

Hope this helps :)

7 0
3 years ago
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Can someone help me ? i have no clue how to figure this out
Ad libitum [116K]

\cos t (\sec t - \cos t) = \sin^2 t

\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t

\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t

1 - \cos^2 t = \sin^2 t

Use the identity: \sin^2 t + \cos^2 t = 1 and solve for \sin^2 t. You get: \sin^2 t = 1 - \cos^2 t

Do the substitution on the left side to get:

\sin^2 t = \sin ^2 t

5 0
3 years ago
Read 2 more answers
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