Answer:
cups plaster of paris.
Step-by-step explanation:
Given:
for one batch of sidewalk chalk =
cup plaster of paris.
Number of bathes = 3
We need to find quantity of plaster of paris.
Solution:
For making 1 batch of sidewalk chalk =
cup plaster of paris.
For making 3 batches of sidewalk chalk =
cup plaster of paris.






Therefore, he needed
cups plaster of paris.
You can count from 34-28 and the numbers you counted (the numbers in between 34-28) is your answer.
Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
_____
<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.
Answer:
h= 62 g=118
Step-by-step explanation:
Answer:
A) 159.135 = X
B) 2,531.25 = X
C) 6,187.5 = X
D) 831,947.46 = X
Step-by-step explanation:
The following investments are required to be calculated:
A) $ 150 at 3% interest for 2 years
B) $ 750.00 at 1/2% interest for 3 years
C) $ 2,250.00 at 1 3/4% interest for 1 year
D) $ 2,550.00 at 3 1/4 interest for 4 years
Therefore, the following calculations must be performed:
A)
150 x (1 + 0.03) ^ 2 = X
150 x 1.03 ^ 2 = X
159.135 = X
B)
750 x (1 + 0.5) ^ 3 = X
750 x 1.5 ^ 3 = X
2,531.25 = X
C)
2,250 x (1 + 1.75) = X
2,250 x 2.75 = X
6,187.5 = X
D)
2,550 x (1 + 3.25) ^ 4 = X
2,550 x 4.25 ^ 4 = X
831,947.46 = X