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vfiekz [6]
3 years ago
10

hanna buys 3 packs of 36 exposure film and 2 packs of 24 exposure film. she uses 8 rolls of film. how many rolls does she have l

eft?
Mathematics
2 answers:
RSB [31]3 years ago
7 0
To solve this problem, first we have to figure out how many total rolls Hanna buys.

3 packs*36 rolls in each pack = 108 total rolls
2 packs*24 rolls in each pack = 48 total rolls

108 rolls + 48 rolls = 156 rolls.

Next, it says that Hanna uses 8 rolls of film.  To model this in our expression, we need to subtract 8 rolls from our total amount.  

156-8 = 146 rolls

Hanna has 146 rolls left.


Arturiano [62]3 years ago
3 0
The question can't be answered with the given information . . . we don't know how many rolls there are in a pack.
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Answer:

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Step-by-step explanation:

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3 years ago
Which matrix represents the system of equations shown below? 3x-5y=12 4x-2y=15
tatuchka [14]

Answer:

\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]

Step-by-step explanation:

When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:

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since our system of equations is:

3x-5y=12\\ 4x-2y=15

we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:

\left[\begin{array}{ccc}3&&\\4&&\\\end{array}\right]

Now for the values of y we hvae -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:

\left[\begin{array}{ccc}3&-5&\\4&-2&\\\end{array}\right]

Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:

\left[\begin{array}{ccc}3&-5&12\\4&-2&15\\\end{array}\right]

usually there is a line separating the columns for the values of x and y, and the independent values:

\left[\begin{array}{ccc}3&-5  &|12\\4&-2  &|15\\\end{array}\right]

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3 years ago
What is a other name for the set of all x-values
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Answer:

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Step-by-step explanation:

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My name is Ann [436]

Answer:

See Explanation.

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  1. Brackets
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  3. Exponents
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Equality Properties

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<u>Algebra I</u>

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Linear Regression

Step-by-step explanation:

We can draw any best line of fit, as long as it is <em>reasonable</em> around the points that are given.

We can just take 2 points and use slope formula and Slope-Intercept Form to find the equation for the best line of fit.

Using Linear Regression, we can determine the <em>true</em> best line of fit using graphing utilities.

<u>Finding the best line of fit</u>

<em>Define 2 points</em>

Point (21600, 205)

Point (27000, 290)

<em>Find slope m</em>

  1. Substitute in point [SF]:                    \displaystyle m=\frac{290-205}{27000-21600}
  2. [Fraction] Subtract:                           \displaystyle m=\frac{85}{5400}
  3. [Fraction] Simplify:                            \displaystyle m=\frac{17}{1080}

<em>Find equation</em>

  1. Define equation [SIF]:                        \displaystyle y = \frac{17}{1080}x + b
  2. Substitute in point:                            \displaystyle 290 = \frac{17}{1080}(27000) + b
  3. Multiply:                                             \displaystyle 290 = 425 + b
  4. Isolate y-intercept <em>b</em>:                         \displaystyle -135 = b
  5. Rewrite:                                             \displaystyle b = -135
  6. Redefine equation:                           \displaystyle y = \frac{17}{1080}x - 135

Slope-Intercept Form tells us that our slope <em>m</em> = \displaystyle \frac{17}{1080} and our y-intercept \displaystyle b = -135.

Setting this as function f(x), we can see from the graph that it is extremely accurate (Blue line).

<u>Using Linear Regression</u>

Depending on the graphing calc you have, the steps may be different.

Using a graphing calc, we can use statistics and determine the <em>best</em> best line of fit.

When we determine the values, we should see that our equation would be g(x) (Green Line).

<em>Credit to Lauren for collabing w/ me in graphing.</em>

6 0
3 years ago
A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr
Ber [7]

Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

Radius of the pond (r) = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

Now using law of conservation of momentum we can find the V_m value.

m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

And initial velocity of both the man and book i.e V_b_(_i_)=0,\ V_m_(i_)=0

So,

⇒ 0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m

⇒ Plugging the values.

⇒ V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}

⇒ V_m=-\frac{1.2\times 4}{76.32}

⇒ V_m=-0.062 ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, V_m = 0.062

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

Let the time taken be t and v\times t = d and d=r then, V_m\times t=r

Then

⇒ t=\frac{radius\ (r)}{V_m}

⇒ Plugging the values.

⇒ t=\frac{4}{0.062}

⇒ t =64 sec

The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

5 0
3 years ago
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