What's the ratio for 55 and 60?
2 answers:
You might be interested in
The figure is made up of a cone and a cylinder.
Diameter = 16 ft
radius = 16÷2 = 8ft
Volume of the cone = 1/3bh
Volume of the cone =
Volume of the cone =
= 402.12
Volume of the cyclinder = bh
Volume of the cylinder =
Volume of the cylinder =
= 1206.37
Total = 402.12 + 1206.37 = 1608.49 cubic feet
Diameter = 16 ft
radius = 16÷2 = 8ft
Volume of the cone = 1/3bh
Volume of the cone =
Volume of the cone =
Volume of the cyclinder = bh
Volume of the cylinder =
Volume of the cylinder =
Total = 402.12 + 1206.37 = 1608.49 cubic feet
Answer:
This appears to be exponential based on the plot of these points
Step-by-step explanation:
See image
The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
The equation for a parabola with vertex (h, k) and vertical scale factor "a" is
y = a(x -h)² + k
One parabola with vertex (6, 9) is
y = (x-6)² +9
y = a(x -h)² + k
One parabola with vertex (6, 9) is
y = (x-6)² +9