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ruslelena [56]
4 years ago
6

You are debating about whether to buy a new computer for $800.00 or a refurbished computer with the same equipment for $640.00.

If a savings account earns 4.5% APR interest, how much do you really save with a refurbished computer if you put the difference into the savings account for a year?
Mathematics
2 answers:
kobusy [5.1K]4 years ago
7 0

Firstly, we need to find the difference between the two. First, we have to take a grand total of $800 and subtract it by the used/refurbished total of $640. After we subtract the two, we would get $160. Next, we want to multiply the $160 by our interest rate. In this case, the interest rate is 4.5%. To convert this to a decimal, we do 0.045. When we multiply $160 by 0.045 we get $7.20. So the final total would be $167.20.

Therefore, you would get $7.20 out of interest!

Xelga [282]4 years ago
3 0
The difference
800−640
=160

160×(1+0.045)
=167.2
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a. To find the least squares regression equation for a group of (x,y) points:

Step 1: For each point(x,y), we need to calculate x² and xy first.

Step 2: Sum all x, y, x² and xy, which gives us Σx, Σy, Σx² and Σxy

Step 3: Calculate Slope m: m = (NΣxy − Σx Σy)/ N(Σx²) − (Σx)² , here N is the number of data.

Step 4: Calculate Intercept b: b = Σy − m(Σx)/ N

Step 5: Assemble the equation as y= mx+b

Here, we have ∑x = 120, ∑y= 1379, ∑x²= 919.5, ∑xy= 10466 and N= 16

So, m= (NΣxy − Σx Σy)/ N(Σx²) − (Σx)²

= \frac{(16*10466)-(120*1379)}{(16*919.5)-(120)^{2}}

= \frac{167456-165480}{14712-14400}

= \frac{1976}{312}

= 6.33

and b = Σy − m(Σx)/ N

= \frac{1379-(6.33*120)}{16}

= \frac{1379-759.6}{16}

= \frac{619.4}{16}

= 38.71

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The approximate test score of a student who sleeps an average of 8 h a night is 89.35%

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