Answer:
The overall expected grade point average for the semester is 3.16/3.1 or 3.2 if you round it up.
Step-by-step explanation:
To get the average, you need to add up all the numbers then divide the sum by how many numbers you added.
3.5 + 3.0 + 3.0 = 9.5
9.5 / 3 = 3.16
Answer: No, it is not a solution
Work Shown:
-2 ≤ k/3
-2 ≤ -9/3
-2 ≤ -3
The last inequality is false because -3 should be smaller than -2 (not the other way around). Use a number line to help see this.
Since the last inequality is false, the original inequality must also be false for that particular k value. Therefore, k = -9 is not a solution.
Answer:
Step-by-step explanation:
since -1≤sin2x≤1 no x values would satisfy the equation
Answer:
False
Step-by-step explanation:
x
The opposite of x is -x
x* -x = -x^2
This is not always 1
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
