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Paul [167]
2 years ago
10

A circle has a diameter of 26 units. What is the area of the circle to the nearest hundred of a square unit?

Mathematics
2 answers:
Nady [450]2 years ago
5 0

Answer: The area is 530 square units

Step-by-step explanation: The diameter of the circle has been given as 26. That makes the radius 13, that is;

Radius = diameter/2

Radius = 26/2

Radius = 13

The area of a circle is derived by the formula;

Area = pi x r^2

Where pi is 3.14 and r is 13,

Area = (3.14) x 13^2

Area = 3.14 x 169

Area = 530.66

Approximately to the nearest hundred of a square unit,

The area of the circle is 530 square units

iVinArrow [24]2 years ago
4 0

Answer:

531 square units

Step-by-step explanation:

Area of a circle = pi r2

Given

Diameter = 26 units

Radius r = diameter/2 = 26/2

= 13units

Pi = 3.14

Therefore

Area = 3.14 x (13)^2

= 3.14 x 13 x 13

= 530.66

= 531 square units

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So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

A+B>C\\A+C>B\\B+C>A

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

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Answer:

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Step-by-step explanation:

Given polynomial is (7 x^3– 4 x^2) + (2 x^3 +3 x)

adding x^3 terms, now we get

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Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

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