Sorry i don’t know if it’s me but i can’t see the picture.
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
Answer:
A 2-column table with 5 rows. Column 1 is labeled Decimal with entries 0.1 6 repeating, 0.3 repeating, 0.5, x, 0.8 3 repeating. Column 2 is labeled Fraction with entries one-sixth, two-sixths, three-sixths, four-sixths, five-sixths.
Which best shows how the table can be used to determine the missing value x?
2(two-sixths) equals four-sixths, so 2(0.5) = 1, and x = 1.
4(1-sixth) equals four-sixths, so 4(0.16) = 0.64, and x = 0.64.
Three-sixths plus one-sixth equals four-sixths, so 0.5 + 0.16 = 0.6, and x = 0.6.
Five-sixths plus one-sixth equals four-sixths, so 0.83 + 0.16 = 0.99, and x = 0.9
7-2(180) = 900°
900 -158 -120 -139 -121 -125 -126
= 111°