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skelet666 [1.2K]
3 years ago
7

Can someone help me plz

Mathematics
2 answers:
Law Incorporation [45]3 years ago
6 0

Answer: The correct answer is C) (0,5)

* Hopefully this helps:) Mark me the brainlliest:)

olchik [2.2K]3 years ago
3 0

Answer:

the answer is C) (0,5)

Step-by-step explanation:

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Write and solve a real world problem involving the multiplication of a fraction and a whole number whose product is between 10 a
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A runner ran 1/2 of a mile for 24 days. How many miles did the runner run in all? (1/2×24=12) Therefore, the runner ran 12 miles in all in the course of 24 days.
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A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?​
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Answer:

  3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

  A = LW = 12a^2

  P = 2(L+W) = 14a

Using the second equation, we can find L:

  L +W = 7a . . . . . divide by 2

  L = 7a -W

Substituting into the area formula gives the quadratic ...

  (7a -W)(W) = 12a^2

  W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

  (W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

  W = 3a, L = 4a

  W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

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The GCF of an odd number and an even number will always be even
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A rectangle and a square have the same area. a. The width of the rectangle is w inches. The length of the rectangle is 15 inches
harkovskaia [24]

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Answer:

  a) w(4w-15)

  b) w²

  c) w(4w -15) = w²

  d) w = 5

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Step-by-step explanation:

a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.

  A = w(4w -15)

__

b) If w is the side length, the area of the square is (also) the product of length and width:

  A = w²

__

c) Equating the expressions for area, we have ...

  w(4w -15) = w²

__

d) we can subtract the right side to get ...

  4w² -15w -w² = 0

  3w(w -5) = 0

This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.

The side length of the square is 5 units.

__

e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.

The rectangle and square have the same width and the same area, so the rectangle must be a square.

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