Rafael must choose a number between 67 and 113 that is a multiple of, 2,4, and 5 . Write all the numbers that he could choose.

1 answer:

5 0

First, find out what the greatest common factor is between 2, 4, and 5.

This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. 

Now we find the list of numbers that are multiples of 20 between 67 and 113. 

The solutions are: 

80 and 100.

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15% of customers that come to your

Helen [10]

Answer:

Number of customers (double taco)= 45

Step-by-step explanation:

Giving the following information:

Double taco order rate= 15% = 0.15

Total number of customers= 300

To calculate the number of customers that order two tacos, we need to use the following formula:

Number of customers (double taco)= Double taco order rate*total number of taco

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2 years ago

The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to th

EleoNora [17]

Answer:

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

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3 years ago

If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.

alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

$\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]$

The inverse of the matrix is

$\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]$

So, the Inverse Transformation is given by

$T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})$