The answer is 10.4 because 5 is counted as higher so it's 10.4.
Answer:
So, exists 5527200 different leadership structures.
Step-by-step explanation:
We know that four members from a 50 person committee are to be randomly selected to serve as chairperson, vicechairperson, secretary, and treasurer. The first perosn to be selected is the chairperson, the second to be selected as vice chairperson, the third is secretary, and the fourth is treasurer.
Since the order of the people is important to us, we have the following:
50·49·48·47=5527200
So, exists 5527200 different leadership structures.
There are 21 red pens. For every 3 red pens, there is 1 blue pen.
Let's make these into a fraction equation.
21/p=3/1
p is the number of blue pens we have yet to find.
First, cross multiply.
21x1=21
px3=3p
Now, we have an equation of
21÷3p
We set it equal to 1, and we solve it.
21÷3p = 1
(21÷3p)×3p=1×3p
21=3p
21÷3=(3p)÷3
7=p
So, if there are 21 red pens, there are 7 blue pens.
We add these together to find the total number of pens the teacher has.
21+7=28
The teacher has 28 pens total.
