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yawa3891 [41]
3 years ago
6

Mike went to a football game with his family. They bought 5 boxes of popcorn, and 3 programs and spent $41. Sean’s family went t

o the same game, bought 3 boxes of popcorn, and 2 programs and spent $26. How much does each program cost at the game?
$4

$5

$6

$7
Mathematics
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

The correct option is D. $7

Step-by-step explanation:

Let cost of each popcorn be x and cost of each program be y

Mike went to a football game with his family. They bought 5 boxes of popcorn, and 3 programs and spent $41

So, The equation which models this situation is given by :

⇒ 5x + 3y = 41 ........(1)

Also, Sean’s family went to the same game, bought 3 boxes of popcorn, and 2 programs and spent $26

So, The equation which models this situation is given by :

⇒ 3x + 2y = 26 .........(2)

On solving equations (1) and equation (2)

We get, x = 4 and y = 7

Hence, Cost of each popcorn at the game = $4

Cost of each program at the game = $7

Therefore, The correct option is D. $7

Elza [17]3 years ago
7 0
5 x + 3 y = 41   / * 3
3 x + 2 y = 26  / * ( - 5 )
-----------------------------
  15 x + 9 y  =  123
+
- 15 x - 10 y = - 130
---------------------------
          - y = - 7   / * ( - 1 )
            y = 7
Answer:
Each program costs    D )  $7
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