The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer:
Width=10
Length=18
Step-by-step explanation:
The length is 2 feet less then twice the width
Let the width be x.
Then the length is 2x -2 based on the given information. Use this to make an equation since it is known that the area is 180feet squared.
x(2x-2)=180
2x^2 - 2x - 180 = 0
2( x^2 - x - 90) = 0
We now have a factorable quadratic.
2(x+9)(x-10)=0
So by zero product property, x=-9, x=10 Since a measure cannot be negative, -9 is an extraneous solution.
So x=10
Then the width is 10 and the length is 18
Hope this helps! Let me know if it is correct!
Answer:
Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.
Answer:
0.07704056
Step-by-step explanation:
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