Question

Rafael wants to buy the same number of gift bags and bows. Gift bags are sold in packs of 6. Bows are sol number of gift bags and bows that Rafael can buy?d in packs of 9. What is the least

Answer 1

Answer: There would be 6 packs of Rafael gift bags and 4 packs of Bows gift bags in 36.

Step-by-step explanation:

Since we have given that

Number of packs of gift bags sold by Rafael = 6

Number of packs of gift bags sold by Bows = 9

So, we need to find the least number of gift bags sold by them is given by

L.C.M of 6 ad 9 = 36

So, there would be 6 packs of Rafael gift bags and 4 packs of Bows gift bags in 36.

Answer 2

Answer:

6 packs of gift bags and 4 packs of bows.  

Step-by-step explanation:  

We have been give that Rafael wants to buy the same number of gift bags and bows. Gift bags are sold in packs of 6. Bows are sold in packs of 9.

To find the least number of bags and bows that Rafael can but we will find least common multiple of 6 and 9.

Multiples of 6 are: 6, 12 ,18, 24, 30, 36, 42,....

Multiples of 9 are: 9, 18, 27, 36, 45,...

We can see that 36 is the least common multiple of 6 and 9.

$\text{The least number of gift bags Rafael should buy}=\frac{36}{6}$

$\text{The least number of gift bags Rafael should buy}=6$

$\text{The least number of bows Rafael should buy}=\frac{36}{9}$

$\text{The least number of bows Rafael should buy}=4$

Therefore, Rafael should buy 6 packs of gift bags and 4 packs of bows to have the same number (36) of gift bags and bows.