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marusya05 [52]
3 years ago
13

Why will a golf ball accelerate faster than a bowling ball when struck by a golf club

Physics
1 answer:
Sergio039 [100]3 years ago
4 0
I think you mean velocity. There is only a downward acceleration (gravitational acceleration) for bodies in free-fall, and their acceleration would be the same. So I'm going to assume velocity.

Using the idea of conservation of momentum, when you swing a a golf club, there is momentum of F*dt. where F is the force and dt is the time of impact. Once you hit the ball, momentum is transferred. Another equation for momentum is m*v which is mass times velocity.

Modeling this we see:

F*dt = m*v

So the larger the mass, the smaller the velocity. Smaller the mass, the larger the velocity. That's why a golf ball's initial velocity is faster.
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What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit
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The highest frequency sound to which the machine can be adjusted is :

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<u>Given data :</u>

Pressure = 10 Pa

Speed of sound = 344 m/s

Displacement altitude = 10⁻⁶ m

<h3>Determine the highest frequency sound ( f ) </h3>

applying the formula below

Pmax = B(\frac{2\pi f}{v}) A --- ( 1 )

Therefore :

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Hence we can conclude that The highest frequency sound to which the machine can be adjusted is : 4179.33 Hz .

Learn more about Frequency : brainly.com/question/25650657

<u><em>Attached below is the missing part of the question </em></u>

<em>A loud factory machine produces sound having a displacement amplitude in air of 1.00 μm, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.31×105 Pa. The speed of sound in air is 344 m/s. What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit?</em>

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