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iogann1982 [59]
3 years ago
6

Ejercicio 1: Un cuerpo gira en un círculo de 8cm de diámetro con una rapidez constante

Physics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

1) The given parameters are;

The diameter of the circle = 8 cm = 0.08 m

The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m

The speed of motion = 7 km/h = 1.944444 m/s

The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²

The centripetal acceleration ≈ 94.52 m/s²

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________ is a change in the position of a body with respect to time relative to a reference point.
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Velocity

Explanation:

Velocity is a vector quantity which is defined as the rate of displacement. Displacement is also a vector quantity which is measured as the shortest distance between the final point form the reference point.

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The time take is  t = 1.3964 \ days

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The electric potential is a scalar unit, so we don't have to struggle with the vectors. The formula that gives electric potential is

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V_a = \frac{1}{4\pi\epsilon_0}\frac{q_1}{r_1} + \frac{1}{4\pi\epsilon_0}\frac{q_2}{r_2}

The distance from the center of the square to one of the corners is \sqrt2 L/2 = 0.035m

V_a = \frac{1}{4\pi\epsilon_0}\frac{2\times10^{-6}}{0.035} + \frac{1}{4\pi\epsilon_0}\frac{-2\times10^{-6}}{0.035} = 0

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U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_3}{r} = Vq_3

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