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iogann1982 [59]
3 years ago
6

Ejercicio 1: Un cuerpo gira en un círculo de 8cm de diámetro con una rapidez constante

Physics
1 answer:
Lera25 [3.4K]3 years ago
8 0

Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

1) The given parameters are;

The diameter of the circle = 8 cm = 0.08 m

The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m

The speed of motion = 7 km/h = 1.944444 m/s

The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²

The centripetal acceleration ≈ 94.52 m/s²

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One small speaker is placed 3m to the east of a second speaker, and a listener stands 4m directly south of one of the speakers.
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Answer:

The value is \lambda  =  2 \  m

Explanation:

From the question we are told that

     The distance of the speaker  from the  second speaker  to the east is  d = 3 \  m

      The distance of the speaker  from the listener  to the south is     a = 4 \  m

Generally given that if the speaker move in any direction, their sound become  louder , it then mean that the position of the listener of minimum sound (i.e a position of minima ) ,

Generally the path difference of the sound produce by both speaker at a position of minima is mathematically represented as

              y =  \frac{\lambda}{2}

Generally considering the orientation  of the speakers and applying Pythagoras theorem we see that  distance from the second speaker to the listener  is mathematically represented as

             b =  \sqrt{d^ 2 + a^2 }

=>           b =  \sqrt{3^ 2 + 4^2 }

=>           b = 5

Generally the path difference between the two speaker with respect to the  listener is  

              y =  b - a

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It makes calculations with very large and small numbers easier.

Scientific notation is a system used in order to It makes calculations with very large and small numbers easier. It is useful as it allows very large number that would take a lot of space to write otherwise, and it allows them to be calculated easier. 10^{23} for example is a incredible large number, but written in this form is immediately understandable and useful for calculation.

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Answer:

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Explanation:

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Using formula of mass

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Answer:

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