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3 years ago

PLZ HELP ME FAST HURRY

Mathematics

1 answer:

iVinArrow [24]3 years ago

3 0

Answer:

Power: (1/5)^3, 2^6

Expanded: 5x5, 6x6x6, 3x3x3/4, 2x2x2x2x2x2

How to say it: 5 raised to the 2nd power, 6 raised to the 3rd power, 3 raised to the 3rd power over 4

Value: 25, 216, 1/125, 9/4, 64

Step-by-step explanation:

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If r = 3.2, what is the area of the shaded region? Round your answer to the nearest hundredth. Use your calculator's value of π.

MrRa [10]

Answer: The shaded area is 99.55 units squared.

Step-by-step explanation:

r = 3.2

Now, we can see that the sides of the square are equal to two times the diameter of the circles (or four times the radius of the circles), so the length of the sides of the square is:

L = 2*(2*3.2) = 12.8

The area of the square is A1 = L^2 = 12.8*12.8 = 163.84 units squared.

the shaded semicircle has a diameter of 4 times r (so the radius is 2 times r), and the area is equal to half the area of a circle:

A2 = (1/2)*pi*(2r)^2 = (1/2)*3.14*(6.4)^2 = 64.31 units squared.

And now we must subtract the area of the four smaller circles inside the square, the area of each one is:

A3 = pi*r^2 = 3.14*(3.2)^2 = 32.15 units squared.

Then the shaded area is:

A = A1 + A2 - 4*A3 = 163.84 + 64.31 - 4* 32.15 = 99.55 units squared.

8 0

4 years ago

Rick buys a spatula costing $2.23. He gives the cashier $5.00. The cashier gives him his change using the least number of coins

Virty [35]

Answer:

2 Dollar Bills

3 quarters

2 pennies

5 0

3 years ago

Sean bought a box of graham crackers for $3.99. He also bought 3 bags

leonid [27]

Answer:

$3.08

Explanation:

You subtract 3.99 from 13.23 which equals 9.24. Because there are three bags of marshmallows, divide 9.24 by 3, which equals $3.08.

4 0

3 years ago

Read 2 more answers

Rachel tutors English. for each hour that she tutors, she earns 50 dollars. Let E be her earnings (in dollars) after tutoring fo

n200080 [17]

Answer:

a. E = 50 H b. 950 dollars

Step-by-step explanation:

a. Since Rachel tutors English for 50 dollars for each hours, her rate is 50 dollar per hour. If she tutors for time, H hours, Her earning E = rate × time = 50 × H

E = 50H.

b. If Rachel's earnings after tutoring for 19 hours is gotten by substituting H = 19 into the equation for the earnings, E.

So, E = 50H

E = 50 × 19

E = 950 dollars.

So, Rachel's earnings after 19 hours is 950 dollars.

4 0

3 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

3 years ago