A:84 b:92 c:88 d:117

The graph of the exponential function models the radioactive decay of

Savatey [412]

Answer:

y=100

Step-by-step explanation:

8 0

3 years ago

What does y equal y-16-3y=0

Afina-wow [57]

Answer:

y = - 8

Step-by-step explanation:

y - 16 - 3y = 0

Group like terms

y - 3y - 16 = 0

Add similar elements: y - 3y = - 2y

- 2y - 16 = 0

Add 16 to both sides

- 2y - 16 + 16 = 0 + 16

Simplify

- 2y = 16

Divide both sides by - 2

$\frac{-2y}{-2}$ = $\frac{16}{-2}$

Simplify $\frac{-2y}{-2}$ : y

$\frac{-2y}{-2}$

Apply the fraction rule: $\frac{-a}{-b} = \frac{a}{b}$

= $\frac{2y}{2}$

Divide the numbers: $\frac{2}{2} = 1$

= y

Simplify $\frac{16}{-2}$ : - 8

$\frac{16}{-2}$

Apply the fraction rule: $\frac{-a}{-b} = \frac{a}{b}$

$-\frac{16}{2}$

Divide the numbers: $\frac{16}{2}$ = 8

= - 8

y = - 8

7 0

3 years ago

20{5[100-2(25+25)+20)]

svetoff [14.1K]

20{5[100-2(50)+20]}
20{5[100-100+20]}
20{5[20]}
20(100)
20000

3 0

3 years ago

Please help! i cant solve it

3241004551 [841]

a ≈ 5.2, B ≈ 50°, C ≈ 95°

Solution:

Given data:

A = 35°, b = 7, c = 9

Using cosine law,

$a^{2}=b^{2}+c^{2}-2 b c \cos A$

$a^{2}=7^{2}+9^{2}-2 (7)(9) \cos 35^\circ$

$a^{2}=49+81-126 (0.82)$

$a^{2}=26.68$

Taking square root on both sides.

a ≈ 5.2

Using sine law,

$$\frac{\sin A}{a} =\frac{\sin B}{b}$

$$\frac{\sin 35^\circ}{5.2} =\frac{\sin B}{7}$

Multiply by 7 on both sides.

$$\frac{0.5735}{5.2}\times 7 =\sin B$

Switch the sides.

Sin B = 0.772

$B=\sin^{-1}0.772$

B ≈ 50°

Sum of all the angles of a triangle = 180°

A + B + C = 180°

35° + 50° + C = 180°

85° + C = 180°

C = 180° - 85°

C = 95°

Hence a ≈ 5.2, B ≈ 50°, C ≈ 95°.

4 0

3 years ago

Assume that 11 people, including the husband and wife pair, apply for 5 sales positions. People are hired at random. (1) what is

Andrew [12]

The probability that both the husband and wife are hired is $\frac{2}{11}$

Explanation

Total number of people = 11 and total number of sales positions = 5

So, the total possible number of ways for selecting 5 people from 11 people will be: $^1^1C_{5}$

Now if both the husband and wife are hired, then it means the remaining (5-2)= 3 positions are filled from the remaining (11 -2) = 9 people.

So, the possible number of ways for selecting 3 people from 9 people will be: $^9C_{3}$

Thus, the probability $= \frac{^9C_{3}}{^1^1C_{5}}=\frac{84}{462}=\frac{2}{11}$

4 0

4 years ago