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Rufina [12.5K]
4 years ago
6

What attributes of the representative model of the parabola can be determined from the standard form

Mathematics
1 answer:
kupik [55]4 years ago
6 0

Answer:

Vertex (h,k)

X intercepts and Y intercepts

Focus

Axis of symmetry

Maximum or minimum value

Step-by-step explanation:

The general form for a parabola or a quadratic function is given by:

f(x) = ax^2 +bx+c

Where a,b and c are real numbers with a \neq 0.

Some features that we can identify from the standard form are:

Ifa>0  the parabola opena upward.

If a the parabola open downwards.

We can find the axis of symmetry . And is defined as x = - \frac{b}{2a}

The x intercepts are given by:

x =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

We can find the x intercept with the following formula:

x = -\frac{b}{2a}

And for the y intercept we just need to use x=0 and we got y=c

And for the y intercept we just need to replace the x intercept into the equation like this:

y = a( -\frac{b}{2a})^2 + b( -\frac{b}{2a})+c

From the standard from we can also find the domain and range. The minimum or maximum value. And we can also find the focus.

You might be interested in
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

5 0
4 years ago
Find the length of DE. Round to the nearest hundredth. (Picture included)
LenKa [72]
Notice the picture
we have, the opposite side
the angle
and we want the hypotenuse

so recall your SOH CAH TOA \bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}  =

which one has all that?  low and behold, is Ms Sine,
so let's bother Ms Sine

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(27^o)=\cfrac{18}{hypotenuse}
\\\\\\
hypotenuse=\cfrac{18}{sin(27^o)}

make sure your calculator is in Degree mode, since the angle here is in degrees, as opposed to Radian mode

8 0
3 years ago
In ΔNOP, \overline{NP} NP is extended through point P to point Q, \text{m}\angle PNO = (x+14)^{\circ}m∠PNO=(x+14) ∘ , \text{m}\a
adelina 88 [10]

Answer:

<OPQ = 23 degrees

Step-by-step explanation:

Given

Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)

Exterior angle = m<OPQ = (5x-2)

The sum of interior angles is equal to the exterior angle, that is;

m∠PNO+m∠NOP = m<OPQ

x+14 + x-1 = 5x-2

2x + 13 = 5x-2

Collect like terms;

2x-5x = -2-13

-3x = -15

x = 15/3

x = 5

Get <OPQ

<OPQ = 5x - 2

<OPQ = 5(5)- 2

<OPQ = 25-2

<OPQ = 23 degrees

4 0
3 years ago
You need to make a pumpkin spice latte in the made Cafe. Per the recipe you add 1/4 cups of pumpkin syrup 1/2 cup of coffee the
blsea [12.9K]
1/2 = 2/4

1/4 + 2/4 = 3/4

4-3= 1

1/4 is milk
3 0
3 years ago
L.c.m of 21,24,26 what is it plz I need answers​
S_A_V [24]

Answer:

LCM of 21,24 and 26 is 2184

Step-by-step explanation:

We need to find LCM of 21,24 and 26

For finding LCM divide the given numbers by a prime number if two of the numbers are divisible by that prime number

 2  |    21,24,26

 2  |    21,12,13

 2  |   21,6,13

 3  |    21,3,13

 7  |   7,1,13

13  |   1,1,13

      |   1,1,1

So, LCM of 21,24 and 26 is: 2 x 2 x 2  x 3 x 7 x 13 = 2184

8 0
3 years ago
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