To find the length, divide the area by the width:
Length = 20.5 / 2.5 = 8.2 cm
Its formula Is h^2=b^2+c^2
and it involves the perpendicular, the base and the hypotenuse of a right triangle only.
Usually in questions, one of the value is not given and we have to solve using the theorem to get the last value
X divided by two is 5
So you multiply 5 and 2 to get 10. Therefore x equals 10
Answer:
x y
-8 -2
-1 -1
0 0
1 1
8 2
Step-by-step explanation:
The given function is
![y=\sqrt[3]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx%7D)
We need to find the y-values for the given t-table.
In the given table the x-values are -8, -1, 0, 1, 8.
At x=-8,
![y=\sqrt[3]{-8}=-\sqrt[3]{2^3}=-2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B-8%7D%3D-%5Csqrt%5B3%5D%7B2%5E3%7D%3D-2)
At x=-1,
![y=\sqrt[3]{-1}=-\sqrt[3]{1^3}=-1](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B-1%7D%3D-%5Csqrt%5B3%5D%7B1%5E3%7D%3D-1)
At x=0,
![y=\sqrt[3]{0}=0](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B0%7D%3D0)
At x=1,
![y=\sqrt[3]{1}=\sqrt[3]{1^3}=1](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B1%7D%3D%5Csqrt%5B3%5D%7B1%5E3%7D%3D1)
At x=-8,
![y=\sqrt[3]{8}=\sqrt[3]{2^3}=2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B8%7D%3D%5Csqrt%5B3%5D%7B2%5E3%7D%3D2)
Therefore, the required table is:
x y
-8 -2
-1 -1
0 0
1 1
8 2