Answer:
(4, 5 )
Step-by-step explanation:
Given the 2 equations
y = x + 1 → (1)
x + 2y = 14 → (2)
Substitute y = x + 1 into (2)
x + 2(x + 1) = 14 ← distribute and simplify left side
x + 2x + 2 = 14
3x + 2 = 14 ( subtract 2 from both sides )
3x = 12 ( divide both sides by 3 )
x = 4
Substitute x = 4 into (1) for corresponding value of y
y = 4 + 1 = 5
Solution is (4, 5 )
1400 or 9,085858585 or balls
Answer: Non of the option.
Step-by-step explanation:
The given equation is
4x^3 - 6x^2 + 15x + 2 = 0
Let's test 1, if it's one of the root. I.e
If x = 1
4 - 6 + 15 + 2 = 15
Positive 1 is not a root to the equation
If x = - 1
-4 - 6 - 15 + 2 = - 23
Negative 1 is not a root
If x = 2
4x8 - 6×4 + 15×4 + 2
32 - 24 + 30 + 2 = 40
Positive 2 is not a root
If x = - 2
4×(-8) - 6×4 - 15×2 + 2
-32 - 24 - 30 + 2 = -84
Negative 2 is not a root
If x = 3
4×27 - 6×9 + 15×3 + 2
108 - 54 + 45 + 2 = 101
Since non of them tend to zero, non of the option is a root of the equation
3k+10=2k-21
move 2k to the other side
sign changes from +2k to -2k
3k-2k+10=2k-2k-21( combine like terms)
3k-2k+10= -21
k+10=-21
move +10 to the other side
k+10-10= -21-10
k= -21-10
answer:
k= -31
