Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is

, and its volume is

. We also know that the area of the larger figure is

; since we don't now its volume, lets represent it with

:



We can conclude that the volume of the larger figure is

; therefore, the correct answer is
a.
we know that
For the function shown on the graph
The domain is the interval--------> (-∞,0]

All real numbers less than or equal to zero
The range is the interval--------> [0,∞)

All real numbers greater than or equal to zero
so
Statements
<u>case A)</u> The range of the graph is all real numbers less than or equal to 
The statement is False
Because the range is all numbers greater than or equal to zero
<u>case B)</u> The domain of the graph is all real numbers less than or equal to 
The statement is True
See the procedure
<u>case C)</u> The domain and range of the graph are the same
The statement is False
Because the domain is all real numbers less than or equal to zero and the range is is all numbers greater than or equal to zero
<u>case D)</u> The range of the graph is all real numbers
The statement is False
Because the range is all numbers greater than or equal to zero
therefore
<u>the answer is</u>
The domain of the graph is all real numbers less than or equal to 
Answer:
Step-by-step explanation:
let the number be x
so according to the question ur equation is
4x=5<x^2
4x-5=x^2
4-5=x^2/x
-1=x
Answer:
Positive 1 over 6 raised to the 2nd power 1/62 or 1 over 36 which is 1/36. To find -6-2, take the inverse of -62.
(first find -62) -62 = -6 * -6 = 36
(then take the inverse of 36, which is 1 over 36) = 1 / 36 = 0.0277
so, -6-2 =0.0277
Step-by-step explanation:
Answer:
No solutions
Explanation:
The given system of equations is
2y = x + 9
3x - 6y = -15
To solve the system, we first need to solve the first equation for x, so
2y = x + 9
2y - 9 = x + 9 - 9
2y - 9 = x
Then, replace x = 2y - 9 on the second equation
3x - 6y = -15
3(2y - 9) - 6y = -15
3(2y) + 3(-9) - 6y = -15
6y - 27 - 6y = -15
-27 = -15
Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.