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andre [41]
3 years ago
13

Owing money can be represented with a negative number. True False

Mathematics
2 answers:
Tom [10]3 years ago
8 0
True, because it's being taken away from you. You're getting rid of that amount and giving it.
sergeinik [125]3 years ago
4 0

Answer:

True

Step-by-step explanation:

I think that is called in debt

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Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.
svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
6 0
3 years ago
Solve p=10a+3b for a
Gre4nikov [31]

Answer:

a = (p - 3b)/10

Step-by-step explanation:

Isolate the variable, a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponents (& roots), Multiplication, Division, Addition, Subtraction).

p = 10a + 3b

First, subtract 3b from both sides.

p (-3b) = 10a + 3b (-3b)

p - 3b = 10a

Next, isolate the a. Divide 10 from both sides.

(p - 3b)/10 = (10a)/10

(p - 3b)/10 = a

a = (p - 3b)/10 is your answer.

~

5 0
4 years ago
the ratio of the number of adults to the number of students at the prom has to be 1:10 lat year there were 477 more students tha
maksim [4K]
You would divide 10 into 477 to get 47.7, but you can't put 47.7 because you can't have a decimal. The answer is 47
8 0
3 years ago
Identify the interval(s) on which the function y = x^2-3x-40 is positive
MakcuM [25]

Answer:

See below

Step-by-step explanation:

x^2-3x-40  Factor

(x - 8) (x + 5)

The x intercepts are -5 and 8

(negative infinity, -5)

(8, positive infinity)

3 0
2 years ago
Michael opens a bag of Skittles and organizes them by color. He has 5 yellow, 6 green, 8
ELEN [110]

Answer:

I think 8:32 because there are 8 oranges and 32 in total

5 0
3 years ago
Read 2 more answers
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