Rearrange the formula given to determine the slope, you will see that in y=mx+b form the slope is -2/3
You now have the slope (m) and two test points. Input those values into y=mx+b and you will have your answer!
I got y=(-2/3)x+(22/3) which I'm quite certain is correct.
Answer:
158.33
Step-by-step explanation:
Answer:
a) 625; 625; right triangle
b) 205; 256; obtuse triangle
Step-by-step explanation:
The squares are values found in your memory or using a calculator. It is straightforward addition to find their sum.
<h3>left side</h3>
7² +24² = 49 +576 = 625
25² = 625
The sum of the squares of the short sides is the square of the long side, so this is a right triangle.
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<h3>right side</h3>
6² +13² = 36 +169 = 205
16² = 256
The long side is longer than is needed to form a right triangle, so the largest angle is more than 90°. This is an <em>obtuse triangle</em> (as shown).
Answer:
5
Step-by-step explanation:
the maximum length is 5 . The 3 tall takes away from the 8 and then your left with 5.
mark brainliest :)
Answer:
The line that meets these conditions is y = 1.5x - 2.5
If you want to use fractions, it would be y = 3x/2 - 5/2
Step-by-step explanation:
To get a line perpendicular to y = -(2/3)x + 1, We can start by finding its slope. That's easy enough as a perpendicular slope is the negative reciprocal of the given one. As this has a slope of -2/3, our new slope has to be 3/2, or 1.5
All we need to do then is express that rate of change relative to the given point (-1, -4). We can do this by expanding the classic equation:
Δy = sΔx
We can write that as such:
y - (-4) = 1.5(x - (-1))
y + 4 = 1.5(x + 1)
y + 4 = 1.5x + 1.5
y = 1.5x + 1.5 - 4
y = 1.5x - 2.5
Or if you want to express those numbers as fractions, it would be y = 3x/2 - 5/2.
To make sure the answer's correct, we can simply plug -1 in as the x value, and see if we get y = -4:
y = 3(-1) / 2 - 5/2
y = -3 / 2 - 5 / 2
y = -8 / 2
y = -4
So we know that our answer is correct (assuming that the slope is correct, which it is - a perpendicular line always has the negative reciprocal of the other line's slope).
