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Mademuasel [1]
3 years ago
10

Which sequence of transformations would maintain congruent ?

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0
218they are the annnns erv
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A baker took 9 hours to bake 6 cakes how long does it take him to bake 1 cake?
AlexFokin [52]

Answer:

1.5 hours

Step-by-step explanation:

5 0
3 years ago
Find the requested function and state domain. <br>Find f·g, for f(x)=1/x-5 and g(x)= 7/x
Flura [38]
We have the following functions:
 f (x) = 1 / (x-5)
 g (x) = 7 / x
 Multiplying the functions we have:
 f · g = (1 / (x-5)) * (7 / x)
 Rewriting:
 f · g = (7 / x (x-5))
 f · g = (7 / (x ^ 2-5x))
 The domain of the function is:
 All reals less:
 x = 0
 x = 5
 Answer:
 
f · g = (7 / (x ^ 2-5x))
 
The domain of the function is:
 
All reals less:
 
x = 0
 
x = 5
6 0
3 years ago
How do you solve simple linear equations
Vera_Pavlovna [14]
It’s easy just make a line and put numbers each line to solve the linear equation and than solve it simple
4 0
3 years ago
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Can someone please help me with my homework?
Aneli [31]

Answer: The answers are: markup, sales tax, 20% tip and gratuities

Step-by-step explanation: All of them increase the price.

5 0
3 years ago
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Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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