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chubhunter [2.5K]
3 years ago
12

If a number line shows tick marks that are not labeled, can you determine the coordinate of a point located at an unlabeled tick

mark?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.

For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.

Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.

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Factor: 25 m 6 −16 25m6−16 (5m3 + 8)(5m3 – 8) (5m3 – 8)2 (5m3 – 4)2 (5m3 + 4)(5m3 – 4)
Liono4ka [1.6K]

Answer:

(5m^3+4)(5m^3-4)

Step-by-step explanation:

(*) A^2 - B^2 =(A+B) (A-B)

25m^6-16=

(5m^3)^2 - 4^2=(*)

(5m^3+4)(5m^3-4)

4 0
3 years ago
:( help? please.. i need help
Oduvanchick [21]
The answer is 64 because they are alternate interior angles. Alternate interior angles are always congruent.
5 0
3 years ago
Shannon delivered 135 muffins to each of 7 restaurants. How many muffins did Shannon deliver?​
Pani-rosa [81]

Answer:

945 muffins

Step-by-step explanation:

135 * 7 = 945

8 0
3 years ago
Read 2 more answers
As a fraction<br> Divide.<br><br> (514)÷(−212)
Marina CMI [18]

Answer:

Exact form:  - 257/106

decimal form: -2.42452830

Mixed Number Form: -2  45/106

Step-by-step explanation:

Reduce the expression if possible by cancelling the common factors

6 0
3 years ago
I need help,I need to use substitution but I don't know how
lions [1.4K]

If y=x+6 and y=-2x-3, then you can replace y in either equation with the equivalent expression given by the other equation. In this case, you have

x+6=-2x-3

and you can solve for x.

x+2x+6-6=-2x+2x-3+6\implies3x=3\implies\dfrac{3x}3=\dfrac33\impliesx=1

Then y=1+6=7.

For the second system, you can write

5x-y=-5\implies 5x-5x-y=-5-5x\implies-y=-5-5x

\implies-(-y)=-(-5-5x)\implies y=5+5x

Then substitute this into the second equation and you get

3x-6(5+5x)=24\implies3x-30-30x=24\implies-27x-30+30=24+30

\implies-27x=54\implies x=2

so that

y=5+5(2)=15

8 0
3 years ago
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