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chubhunter [2.5K]
3 years ago
12

If a number line shows tick marks that are not labeled, can you determine the coordinate of a point located at an unlabeled tick

mark?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.

For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.

Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B4%7D%7Bx%5E%7B2%7D-2x-8%20%7D" id="TexFormula1" title="\frac{2x+4}{x^{2}-2x-8 }
lisabon 2012 [21]

Answer:

\frac{2}{x-4}

Step-by-step explanation:

\frac{2x+4}{x^2-2x-8}

Factor both the numerator and denominator

\frac{2(x+2)}{(x-4)(x+2)}

The x+2 's cancel out

The equation in its simplest form is \frac{2}{x-4}

Hope this helps!

6 0
3 years ago
From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c
sergiy2304 [10]

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

5 0
3 years ago
Read 2 more answers
The time required to do a job varies inversely as the number of people working. It takes 5hr for 7 bricklayers to build a park w
ExtremeBDS [4]

<u>Answer</u>

3.5 hours.


<u>Explanation</u>

The first step is to calculate the constant of proportionality.

t ∝ 1/n

t = k/n   Where t = time, K= constant and n = number of people

t = k/n

k =tn

   = 5×7 = 35

The equation becomes;

t = 35/n

for n = 10,

t = 35/10

  t = 3.5 hours.

6 0
3 years ago
What is the equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3?
Alika [10]
<h3><u><em>Option B</em></u></h3><h3><u><em>The equation of a line, in point- slope form, that passes through (5, -3) and has a slope of 2/3</em></u></h3><h3><u><em /></u>y + 3 = \frac{2}{3}(x -5)<u><em /></u></h3>

<em><u>Solution:</u></em>

<em><u>The equation of line in point slope form is given as:</u></em>

y - y_1 = m(x-x_1)

Where, "m" is the slope of line

Given that,

slope = 2/3

m = \frac{2}{3}

The line passes through (5, -3)

Substitute m = 2/3 and (x_1, y_1) = (5, -3) in point slope form

y - (-3) = \frac{2}{3}(x -5)\\\\y + 3 = \frac{2}{3}(x -5)

Thus equation of line in point slope form is found

8 0
3 years ago
Find the area of the figure.
Contact [7]

area of rectangle= 8*13=104m^2

base of the Triangle= 13 -(4+4)=5

area of Triangle = 5*6/2=15m^2

area of shaded shape =104-15= 89m^2

7 0
3 years ago
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