It belongs to the rational numbers.
It is the ratio of two integers, 2 and 3.
Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
Answer: Part A: a square pyramid Part B: 84 square feet
Step-by-step explanation:
Part A: The shape will have a base that is a square with triangles on each of its edges that connect at a point at the top.
Part B: The amount of nylon needed is the surface area of the net. There is a square and two triangles. The square has a side length of 6 so its area will be 6*6=36 square feet. Each triangle has a base of 6 and a height of 4 so each of their areas will be
square feet. Adding up the area of the 4 triangles and the square gives us 4*12+36=84 square feet.
Answer:
This question requires a comparison between two different variables 6% and 16% values. If we let x=$ loaned on 6% loans and y=$ loaned on 16% loans, then we can relate two equations.
0.06x + 0.16y = $1500 --> referencing the interest earned from each percentage loaned.
x + y = $16000 --> referencing the total amount of money loaned out.
Rearrange either equation and substitute for a value in the other equation or use elimination to determine each individual variable.
Step-by-step explanation: