Question

Use the substitution method to solve each linear system. 4x - 3y = -13,-2x + y = 4

Answer 1

Answer:

The solutions to the system of equations are:

$x=\frac{1}{2},\:y=5$

Step-by-step explanation:

Given the system of the equations

$\begin{bmatrix}4x-3y=-13\\ -2x+y=4\end{bmatrix}$

Isolate x for for 4x-3y=-13

$4x-3y=-13$

$4x=-13+3y$

Divide both sides by 4

$x=\frac{-13+3y}{4}$

substitute y=5

$x=\frac{-13+3\cdot \:5}{4}$

$x=\frac{1}{2}$

The solutions to the system of equations are:

$x=\frac{1}{2},\:y=5$