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3 years ago

2nq=3+7nq solve for n thanks

Mathematics

2 answers:

Gnesinka [82]3 years ago

7 0

Answer:

n = - $\frac{3}{5q}$

Step-by-step explanation:

Given

2nq = 3 + 7nq ( subtract 7nq from both sides )

- 5nq = 3 ( divide both sides by the multiplier - 5q )

n = $\frac{3}{-5q}$ = - $\frac{3}{5q}$

Nataly_w [17]3 years ago

5 0

Answer:

n= -3/q

Step-by-step explanation:

2nq-7nq=3

-5nq=3

n = -3/q

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Demand for cola : 100 – 34x + 5y

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x(100 – 34x + 5y) + y(50 + 3x – 16y)

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Solving (i) and (ii),

4 x (i) ⇒ 272x - 32y = 400

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3 years ago

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A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

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C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

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2 years ago

Please help fast i am struggling

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B is the correct answer for your question I do believe, I hope that helped you. If not I am sorry, I tried to answer fast for you.

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3 years ago

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