1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Cerrena [4.2K]
3 years ago
11

How many hours is 9:30 to 4:00pm

Mathematics
2 answers:
Nitella [24]3 years ago
7 0
Just count up from 9:30. 5 and 1/2 hours is the answer
Luda [366]3 years ago
3 0
Starting point = 9:30am 

10:30   1hr

11:30    2hr

12:30    3hr

1:30       4hr
 
2:30      5hr

3:30     6hr

30 min  30 min  

6hr 30 mins
You might be interested in
Goofy's fast food center wishes to estimate the proportion of people in its city that will purchase its products. Suppose the tr
Setler79 [48]

Answer:

\mu_{\hat p}= 0.06

\sigma_{\hat p}= \sqrt{\frac{0.06*(1-0.06)}{280}}= 0.0142

And we want to find this probability:

p(\hat p

z = \frac{p \mu_{\hat p}}{\sigma_{\hat p}}

z = \frac{0.09-0.06}{0.0142}= 2.114

And we can find this probability:

P(z

And using the normal table or excel we got:

P(z

Step-by-step explanation:

For this case we have the following info given:

n = 280 represent the sample size

p =0.06 represent the true proportion

The sample proportion can be approximated with this distribution:

\hat p \sim N (p ,\sqrt{\frac{p(1-p)}{n}})

The mean is given by:

\mu_{\hat p}= 0.06

And the deviation is given by:

\sigma_{\hat p}= \sqrt{\frac{0.06*(1-0.06)}{280}}= 0.0142

And we want to find this probability:

p(\hat p

And we can use the z score formula given by:

z = \frac{p \mu_{\hat p}}{\sigma_{\hat p}}

And replacing we got:

z = \frac{0.09-0.06}{0.0142}= 2.114

And we can find this probability:

P(z

And using the normal table or excel we got:

P(z

4 0
3 years ago
Sara and Miguel need to travel 185.5 miles. They would like to arrive in 3.5 hours. What must be their average speed, in mph?
adelina 88 [10]
185.5 divided by 3.5 equals 53
53 mph
4 0
4 years ago
Read 2 more answers
( Help ASAP ) y varies inversely with x. If x is 6.4 when y is 1.5, what is k, the constant of inverse variation?
DiKsa [7]

Answer:

k = 9.6

Step-by-step explanation:

When dealing with inverse variation, the two variables vary in opposite directions. This means that as the first variable increases, second variable decreases and as the first variable reduces,the second variable increases.

Y varies inversely with x.

So as y increases, x reduces and as y reduces, x increases.

We would proceed by introducing a constant of variation, k

y = k/x

From the information given,

The constant of variation = k

The value if x = 6.4

The value of y = 1.5

To find the value of k

y = k/x

k = yx = 1.5 × 6.4

k = 9.6

7 0
4 years ago
Please help me answer this :)
eduard
Answer
A
Why?
He did not distribute 2/3 to the x
3 0
3 years ago
Buses to exeter leave a bus station every 20 minutes.Buses to Plymouth leave the bus station every 16 minutes A bus to exeter an
Eva8 [605]
9:20 am
Lcm is 80 so 80 minutes after 8 am is 9:20
6 0
3 years ago
Other questions:
  • I honestly don't know how to complete this problem. Please help may you include the steps also.
    10·1 answer
  • Weight in slope intercept form. 2x+y=2
    11·2 answers
  • Special precision bolts are made by another machine. These are for jobs that require more exact measurements. The bolts must be
    12·1 answer
  • Does this polynomial have a GCF greater than 1?
    7·1 answer
  • Care este volumul unui paralelipiped dreptunghic?
    8·1 answer
  • Write the equation of the line that passes through (-3,5) and (2, 10) in slope-intercept form. (2 points)
    8·1 answer
  • What is the midpoint of the line segment with the endpoints J(-9,-4) and K(7,8)?
    13·1 answer
  • PLEASE HELPP!!! (look at picture)
    10·1 answer
  • Simplify this expression: 1/2(10x + 12) - (3.5x - 7) *
    13·1 answer
  • Sin A - sin B - sin C=-4cos A 2 .sin B 2 .sin C 2​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!