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larisa [96]
3 years ago
7

A game of basketball requires to players. at the park there are 5 games being played. how many total player are at the park

Mathematics
1 answer:
lara [203]3 years ago
5 0
If one game needs two* players, and there are 5 games,
you multiply two by five to get ten players total.
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Solve the quadratic equation by completing the square. x2 + 6x + 7 = 0
ruslelena [56]
Hello,

x²+2*3x+3²+7-9=0
==>(x+3)²-2=0
==>(x+3-√2)(x+3+√2)=0
==> x=-3+√2 or x=-3-√2
7 0
3 years ago
xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc
leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ <u>28.6 km</u>

<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

4 0
3 years ago
If the monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be distributed as
Y_Kistochka [10]

Answer:

A) About $195.00

Step-by-step explanation:

In a normal distribution, the interval (mean - 3*standard deviation, mean + 3*standard deviation) account for about 99.7% of the values. In this case mean + 3*standard deviation = $87.00 + 3*$36.00 = $195.00. So, it 's expected that this amount of money would be the largest individual customer bill.

4 0
3 years ago
The relationship between angles a and b?​
Rina8888 [55]

Answer:

They are both acute angles

7 0
3 years ago
Read 2 more answers
3.8*10 to the 9th power divided by 4*10 to the 2nd power
user100 [1]

Answer:

9.5\times 10^{6}

Step-by-step explanation:

1. Divide the coefficients and the exponentials separately

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = \dfrac{3.8}{4} \times \dfrac{10^{9}}{10^{2}}

2. Divide the coefficients

\dfrac{3.8}{4} = 0.95

3. Divide the exponentials

Subtract the exponent in the denominator from the exponent in the numerator.

\dfrac{10^{9}}{10^{2}} = 10^{(9 - 2)} = 10 ^{7}

4. Re-join the new coefficient and the new exponential

\dfrac{3.8 \times 10^{9}}{4 \times 10^{2}} = 0.95 \times 10^{7}

5. Put the new number into standard form

The number before the power of 10 must be greater than or equal to one and less than 10.

Multiply the answer by 10/10.

(0.95 \times 10^{7}) \times \dfrac{10}{10} = (0.95\times10) \times \dfrac{10^{7}}{10} = \mathbf{9.5\times 10^{6}}

5 0
3 years ago
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