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3 years ago

8

Choose the correct simplification of the expression f to the 6th power times h to the 9th power all over f to the 3rd power time

s h to the 7th power.

2 answers:

maria [59]3 years ago

6 0

That doesn't make sense

Mrac [35]3 years ago

5 0

(f*6 h^9)/(f^3 h^7) =
The exponent rule for division is 'keep the base and subtract the powers'
f^3 h^2

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Consider r (x) = StartFraction a x Superscript b Baseline + 8 Over c x Superscript d Baseline EndFraction, where a, b, c, and d

madam [21]

Answer:

The correct answer is 0 or choice A on edge

Step-by-step explanation:

right on edge

4 0

2 years ago

If Ill m, solve for x.<br> (8x - 71)<br> (5x + 7)<br> x =

horsena [70]

Answer:

x=26

Step-by-step explanation:

by definition of alternate exterior angle rule 8x -71 = 5x +7

What you want to do is get your X's on one side I recommend subtracting 5x so that you don't have to deal with negative values.

8x-5x-71=5x-5x+7

3x-71=7

add 71 to both sides the goal now is trying to get by itself

3x-71+71=7+71

3x=78

now divide both sides by 3

3x/3=78/3

x=26

8 0

3 years ago

Read 2 more answers

Find the sum of the measures of the interior angles of a convex 37-gon.

wel

You will use the polygon sun theorem.

(N-2)(180)

Plug in you're number for N
(37-2)(180)

Can you figure out how to solve the rest of the problem?

5 0

2 years ago

Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. Y=4.5 when x = 3

Nookie1986 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=4.5\\
x=3
\end{cases}\implies 4.5=\cfrac{k}{3}\implies 4.5(3)=k
\\\\\\
13.5=k\qquad therefore\qquad \boxed{y=\cfrac{13.5}{x}}$

8 0

2 years ago

Express secΦ in terms of tanΦ

Sunny_sXe [5.5K]

Answer:

$\sec\theta=\sqrt{1+\tan^2\theta}$

Step-by-step explanation:

The trigonometric identity is :

$\sec^2\theta-\tan^2\theta=1\\\\or\\\\\sec^2\theta=1+\tan^2\theta$

We need to express secθ in terms of tanθ.

The above equation becomes,

$\sec\theta=\sqrt{1+\tan^2\theta}$

Hence, this is the required solution.

5 0

2 years ago