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postnew [5]
3 years ago
8

Choose the correct simplification of the expression f to the 6th power times h to the 9th power all over f to the 3rd power time

s h to the 7th power.
Mathematics
2 answers:
maria [59]3 years ago
6 0
That doesn't make sense
Mrac [35]3 years ago
5 0
(f*6 h^9)/(f^3 h^7) =
The exponent rule for division is 'keep the base and subtract the powers'
f^3 h^2
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RoseWind [281]

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35) 352.14

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2 years ago
Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?
Aneli [31]
That answer was (B)................
3 0
3 years ago
The answer I need this answer emergency pls help
HACTEHA [7]

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Step-by-step explanation:

4 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
Plz help I will mark brainliest if correct ​
Alekssandra [29.7K]

Answer:

A ................................

6 0
3 years ago
Read 2 more answers
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