The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
<h3>What is the average rate of change?</h3>
The average Rate of Change of the function f(x) can be calculated as;
Interval -3 ≤ x ≤-1
a = -3, b = -1
f(a) = f(-3) = -20
f(b) = f(-1) = 0
Step 2: Find Average
Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.
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Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Hey again!
The answer to your question is 10 meters.
We can solve this by multiplying 15 and 2/3, and you get 10
Hope it helps!
Answer:
1. Translate circle A using the rule (x − 3, y + 4).
4. Dilate circle A by a scale factor of 5
Step-by-step explanation:
we know that
All circles are similar figures
step 1
Translate the center of circle A to the center of circle B
we have
A(2,8) -----> B(5,4)
so
The rule of the translation is
(x,y) ----> (x+a,y+b)
(2,8) ----> (2+a,8+b)
2+a=5 ----> a=5-2=3
8+b=4 ---> b=4-8=-4
therefore
The rule of the translation is
(x,y) ----> (x+3,y-4)
step 2
Divide the radius of circle B to the radius of circle A to find out the scale factor
10/2=5
so
Multiply the radius of circle A by the scale factor to obtain the radius of circle B
therefore
Dilate circle A by a scale factor of 5
