The perimeter of the base of a regular quadrilateral prism is 32 cm. The height of the prism is 2 times greater than the length

Question

Elanso [62]

2 years ago

8

The perimeter of the base of a regular quadrilateral prism is 32 cm. The height of the prism is 2 times greater than the length

of the base edge. Find the sum of all edges of the prism.

Mathematics

1 answer:

horsena [70] · Answer 1 · 2022-05-12T21:01:46+03:00

A regular quadrilateral prism has 12 edges. It is given perimeter of the base 32 cm. Length of each edge of base will be 32÷4=8 cm. The 4 edges at the top will also have the same number of edges that is 4 with measure 8cm each.

Given: The height of the prism is 2 times greater than the length of the base edge.Height of prism = 2(8)= 16cm. Number of edges with measure 16 cm is 4.

Sum of all the 12 edges= 8+8+8+8+16+16+16+16+8+8+8+8=128 cm.