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3 years ago

Ben buys a car for $50,000. The value of the car decreases at a rate of 4% per year. How much will the car be worth in 3 years?

Mathematics

2 answers:

muminat3 years ago

7 0

Answer:

The answer is 44,237.

Step-by-step explanation:

50000×0.96×0.96×0.96

=44236.8

when rounded to the nearest dollar it is 44,237.

MaRussiya [10]3 years ago

6 0

50000*0.04*3=6000,,50000-6000=44000

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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Mars2501 [29]

Answer:

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Step-by-step explanation:

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20÷2=10

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LenaWriter [7]

I think it is 22.5, since molly has 75% of the packs

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3 years ago

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nadezda [96]

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Fudgin [204]

Answer:

Step-by-step explanation:

when a number x is added to it's square, the total is 12. find two possible values of x

x+x^2=12

x^2+x=12

x^2+x−12=12−12

x^2+x−12=0

(x−3)(x+4)=0

x−3=0 or x+4=0

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