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Sidana [21]
3 years ago
13

The domain of the function f(x) = 3x3 is {2, 5}. What is the function’s range?

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0
The domain is {2,5} which the set containing the numbers 2 and 5. I'm assuming that the function is f(x) = 3x3<span>. So...

</span>when x = 2, f(x) = 3*23<span> = 3*8 = 24.
</span>when x = 5, f(x) = 3*53<span> = 3*125 = 375.

so this means the functions range is {24, 375}

hope this helped you out</span>
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Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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What is equivalent to 3squareroot of 8^x
inn [45]

Answer:

3 * 8^(x/2)

Step-by-step explanation:

The third answer choice is the correct one.

Here's how:

3squareroot of 8^x = 3√(8^x)  = 3*(8^x)^(1/2)  =  3 * 8^(x/2)

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Nadya [2.5K]

Answer: b) rolled three times, number of 2s rolled

              d) rolled twice, number of odds rolled

<u>Step-by-step explanation:</u>

A binomial experiment must meet the following criteria:

  1. There must be a fixed number of trials (rolls)
  2. Each trial (roll) is independent of the others
  3. There are only two outcomes (success or fail)
  4. The probability of each outcome remains constant from trial to trial

a) rolled twice --> satisfies #1 & #2 (n = 2)

   X is the sum --> fails #3 (more than two outcomes)

b) rolled three times --> satisfies #1 & #2 (n = 3)

   X is the number of 2s rolled --> satisfies #3 & #4 (P success = 1/6)

c) rolled an unknown number of times - fails #1

d) rolled twice --> satisfies #1 & #2 (n = 2)

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