You need to provide a screenshot or recreation of the rest of the problem's information.
Answer:
this is a rubric for an assignment not the work :)
Step-by-step explanation:
yay brainlyest
Answer:
x = 11/9
Step-by-step explanation:
Eliminate parentheses, add 16x, subtract 21.
7(3 -x) = 8(4 -2x) . . . . given
21 -7x = 32 -16x . . . . . eliminate parentheses using the distributive property
9x +21 = 32 . . . . . . . . add 16x
9x = 11 . . . . . . . . . . . . subtract 21
x = 11/9 . . . . . . . . . . . .divide by the coefficient of x
2 bags = 4 feeders
You need 40 feeders.
40 feeders (need to fill up) ÷ 4 (feeders per 2 bags) = 10
10 x 2 (bags) =
20 bags for 40 feeders
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
