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Neporo4naja [7]
3 years ago
12

micah uses 2 bags of birdseed to fill up 4 bird feeders. how many bags wi'll he need to fill up 40 feeders?

Mathematics
2 answers:
vekshin13 years ago
7 0
2*2 = 4
40/2 = 20

Micah needs half the number of birdseed bags in order to fill up a certain number of bird feeders. He would need 20 bags to fill up 40 feeders.
Gre4nikov [31]3 years ago
3 0
2 bags = 4 feeders
You need 40 feeders.
40 feeders (need to fill up) ÷ 4 (feeders per 2 bags) = 10
10 x 2 (bags) =
20 bags for 40 feeders

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Help asap plsssssss ​
balu736 [363]

Answer:

B.) Associative Property of Addition

Step-by-step explanation:

This is because none of the numbers change places the only things that move are the parenthesis which correspond with the associative property.

4 0
3 years ago
A washer and a dryer cost $995 combined. The washer cost $45 more than the dryer. What is the cost of the dryer?​
Talja [164]

When a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

The combined cost of a washer and a dryer = $995

Consider the cost of a dryer as x

The washer cost $45 more than the dryer.

The cost of the washer = x+45

Then the equation will be

x+x+45 = 995

2x+45 = 995

2x = 950

x = 950/2

x = 475

The cost of the dryer is $475

Hence, when a washer and a dryer cost $995 combined. If  the washer cost $45 more than the dryer, then the cost of the dryer is $475

Learn more about equation here

brainly.com/question/1625308

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8 0
1 year ago
Please help me thanks
BabaBlast [244]

Answer:

16.7

Step-by-step explanation:

We can use the Pythagorean theorem, a^2 + b^2 = c^2.

a = 11

c = 20

11^2 + b^2 = 20^2

121 + b^2 = 400

b^2 = 279

b = sqrt(279) = 16.7

5 0
3 years ago
Please help with my math
AleksAgata [21]
$1.44

each one cost 0.24
0.24 x 6 = 1.44
7 0
3 years ago
Read 2 more answers
WARNING : NON SENSE ANSWER REPORT TO MODERATOR ​
Rzqust [24]

Answer:

\frac{180}{147}

Step-by-step explanation:

  • Simplify (\frac{3}{-7} - \frac{11}{21} )

=> \frac{(-3 \times 3) - 11}{21}

=> \frac{-9 - 11}{21}

=> \frac{-20}{21}

  • Find the additive inverse of  \frac{-20}{21} by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of  \frac{-20}{21}.

=> x + \frac{-20}{21} = 0

=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}

  • Simplify (\frac{9}{5} \div \frac{7}{5} )

=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }

=> \frac{9}{5} \times \frac{5}{7}

=> \frac{9}{7}

  • Now, find the product of \frac{9}{7} & \frac{20}{21}

=> \frac{9}{7} \times \frac{20}{21}

=> \frac{180}{147}

3 0
3 years ago
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