Question

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 - 10x?

Answer 1

Answer:

x = $5 - \sqrt{31}$, $5 + \sqrt{31}$

Step-by-step explanation:

6 = x^2 - 10x

0 = x^2 - 10x - 6

Let's use the quadratic formula. ( $x = \frac{-b +- \sqrt{b^2 - 4ac}}{2a}$)

$x = \frac{10 +- \sqrt{-10^2 - 4(-6)}}{2}$

x = $\frac{10 +- 2\sqrt{31} }{2}$

  = 5 +- $\sqrt{31}$

x = $5 - \sqrt{31}$, $5 + \sqrt{31}$