<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
<em>Your answer is the following.</em>
<em></em>
<em>Answer = 19/50
</em>
<em />
Answer:
The probability is 0.017429
Step-by-step explanation:
We start by calculating the z-score
Mathematically;
z-score = (x-mean)/SD/√n
In this case;
x = 273
mean = 276
SD = √(variance) = √81 = 9
n = 40
Substituting these values into the z-score formula, we have that;
z = (273-276)/9/√40
z = -2.11
So we proceed to get the probability
the probability in this case is;
P( z < -2.11)
We can use the normal distribution table for this
Our answer will be
P( z < -2.11) = 0.017429
angle 2 is congruent to angle six
It’s either B or C, I’m not really sure
