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3 years ago

1. Suppose that cos B = 0.68. What is the value of sin(a)? Explain.

Mathematics

1 answer:

Papessa [141]3 years ago

5 0

The value of Sin(a) suppose that Cos B = 0.68 in which case, a + B = 90° is; 0.68.

<h3>Trigonometry</h3>

First, when we have two angles, whose sum equals, 90°.

In essence, Since the algebraic sum of angles A and B is 90°;

A + B = 90.

B = 90 -A.

By trigonometric identity;

Sin A = Cos (90 - A)

Where; (90 - A) = B.

Therefore; Sin A = Cos B = 0.68.

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A supplier sold a scanner machine for Rs 41,400 with 15% VAT after allowing 10% discount on it's marked price and gained 20%. By

victus00 [196]

Answer:

Selling price with VAT {15%} = Rs 41400

S.P +15% of S.P =Rs 41400

S.P(1+15%)=Rs 41400

S.P=Rs 41400/1.15

Selling price without VAT =Rs 36000

Again

Discount = 10%

M.P =S.P+ Discount % of M.P

M.P-Discount% of M.P= S.P

M.P(1-Discount%)=Rs 36000

M.P(1-10%)=Rs 36000

M.P=Rs 36000/0.9

Marked Price = Rs 40,000

again

Discount =Discount % of M.P

=10% of 40000

=Rs 4,000

Again

Profit=20%

For 20% profit

Cost price = (S.P*100)/(100+profit%)

=(36000*100)/(100+20)

= Rs 30000

For 24% profit

selling price = (100+profit%)*C.P/100

=(100+24)*30000/100

=Rs 37200

Again

Discount = 40000–37200 = Rs2800

Discount % = discount/M.P*100%

=2,800/40,000* 100 = 7%

Finally

Discount percent to be reduced =10%–7%= 3%

3 0

2 years ago

The weights of college football players are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds

Feliz [49]

Answer:

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 200, \sigma = 50$

Find the probability that he weighs between 170 and 220 pounds.

This is the pvalue of Z when X = 220 subtracted by the pvalue of Z when X = 170.

X = 220

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{220 - 200}{50}$

$Z = 0.4$

$Z = 0.4$ has a pvalue of 0.6554

X = 170

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{170 - 200}{50}$

$Z = -0.6$

$Z = -0.6$ has a pvalue of 0.2743

0.6554 - 0.2743 = 0.3811

0.3811 = 38.11% probability that he weighs between 170 and 220 pounds.

6 0

4 years ago

Could Someone give me a run down of how these problems are done? i used a calculator to get the answers but now i want to know h

morpeh [17]

It’s just the same as if there were no decimal point. but if there isn’t a number in the quotient on the left of the decimal like #15, then you just place a 0 and continue to the next dividend which is 50.