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Ierofanga [76]
3 years ago
5

The square root of 104 is between which two integers?

Mathematics
1 answer:
olganol [36]3 years ago
7 0

Answer: 10 and 11

Step-by-step explanation: The best way to think about it is to think of the squares of numbers that equal close to 104. 10 squared is 100, and 11 squared is 121. Since 104 is between these two, we can assume that the square root of 104 must be in between their square roots, 10 and 11.

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A list of consecutive integers begins with m and ends with n. If n - m = 66, how many integers are in the list?
patriot [66]

Answer:

67.

Step-by-step explanation:

n - m = 66

The 66 includes the number m+1   up to and including n (buy not m).

So the number of integers is 66 +1 = 67

5 0
2 years ago
Find the zeroes of the function f(x).<br> f(x)=(x–3)(x+4)
Ymorist [56]

Answer:Set \displaystyle f\left(x\right)=0f(x)=0.

Step-by-step explanation:

Set \displaystyle f\left(x\right)=0f(x)=0.

If the polynomial function is not given in factored form:

Factor out any common monomial factors.

Factor any factorable binomials or trinomials.

Set each factor equal to zero and solve to find the \displaystyle x\text{-}x- intercepts.

5 0
2 years ago
HELP ME PLEASE!!!
zaharov [31]

The correct answer to this question would be answer choice B.

To convert the decimal 0.56 to a fraction, first set it to a fraction over 100 which would be 56/100.

Then, because the question asks for the fraction to be in simplest form, look for the greatest common factor of the numerator and denominator or 56 and 100.

To find it, list out all of their factors:

56: 1, 2, 4, 7, 8 , 14, 28, 56

100: 1, 2, 4, 5, 10,20,25,50,100

Notice that out of all the factors listed, the greatest common factor listed is 4. Because of this, divide both the numerator and denominator by 4 to simplify your fraction to your answer: 14/25

5 0
3 years ago
the sum of three numbers is 131. the third number is 4 times the first. the second number is 5 more than the first. what are the
Sphinxa [80]

Step-by-step explanation:

let the numbers are:

a, b, and c

the equation would be:

a+b+c = 131

c = 4a

b = a+5

=>

a + a+5 +4a = 131

6a +5 = 131

6a = 131-5

6a = 126

a= 126/6

a = 21

b = a+5 = 21+5

b = 26

c = 4a = 4(21)

c = 84

4 0
2 years ago
Can someone help me find y PLEASE
Maurinko [17]
pretty sure it’s 42
4 0
3 years ago
Read 2 more answers
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