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lakkis [162]
3 years ago
12

Write the following proportion: 8 is to 64 as 2 is to x.

Mathematics
2 answers:
denis-greek [22]3 years ago
6 0
8^2=64
2^2=4

Good luck with your math.
Ksenya-84 [330]3 years ago
3 0
x = 4

8 multiplied by itself is 64.
And so, 2 times itself is 4.
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Can anyone explain how to solve this please?
Virty [35]
I'd start by squaring everything, personally.


4 0
3 years ago
14. Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,3) E (8,3) and F(1,-5). Show your work.
Stells [14]
As in the solution of all geometry problems, the first step is to draw a diagram.  In this case, we see a right-triangle for which finding the circumcentre is almost trivial.

Recall that the circumcentre is the centre of a circle which passes through all three points D, E and F (shown as A,B & C in the attached figure).

The circumcentre can be found by the intersection of the perpendicular bisectors of the three sides.  Since the three bisectors are concurrent, we only need the intersection of any two perpendicular bisectors out of the three.

In a right triangle where the legs are parallel to the axes, the intersection of the perpendicular bisectors can be found by inspection.

In the given case, 
mid-point of DE (shown as AB) = ((1+8)/2, 3) = (4.5,3)
   perpendicular bisector of DE :  x=4.5
mid-point of DF (shown as AC) = (1, (3-5)/2) = (1,-1)
   perpendicular bisector of DF :  y=-1

Therefore the circumcentre is the intersection of x=4.5 and y=-1, or
   circumcentre = (4.5,-1)

which brings us to the interesting property of the circumcentre of a right-triangle:  The circumcentre of a right triangle is located at the mid-point of the hypotenuse.

7 0
3 years ago
Read 2 more answers
Please answer thisssssssssss
sweet-ann [11.9K]

Answer:

Range = 3

Step-by-step explanation:

Data set : 0, 0, 0, 0, 1, 1, 1, 2, 2, 2, 2, 3, 3

Range = Largest Number — Smallest Number

Range = 3 - 0

Range = 3

Hope this helps!

5 0
3 years ago
760 hundreds using place-value chart
vazorg [7]
7hundreds 6tens 0ones
7 0
3 years ago
99 Points Need Help! How to reflect over y= -x+6
iragen [17]
To reflect in the line y = -x + 6, we translate everything down 6 first. This will make it seem like we are reflecting in the line y = -x
                                 (x,y) → (x, y-6)
Then, to reflect in the line y = -x, we switch the x- and y-coordinates and then make them negative
                                 (x,y) → (-(y-6), -x)     
Then we move everything back up again
                                 (x,y) → (-(y-6), -x + 6)          
I will present to you an example. Reflect the point (-4, 8) in the line y = -x + 6.
                                 (-4,8) → (-(8-6), -(-4) + 6) → (-2, 10)
You should graph this out to confirm with the reflection line.
6 0
3 years ago
Read 2 more answers
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