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Illusion [34]
3 years ago
15

Solve for k. -21 -3 21

Mathematics
2 answers:
k0ka [10]3 years ago
7 0

Answer:

k = -21

Step-by-step explanation:

9/ (2k-3) = 4/(k+1)

Using cross products

9 * (k+1) = 4(2k-3)

Distribute

9k+9 = 8k -12

Subtract 8k from each side

9k-8k +9 = 8k-8k-12

k+9 = -12

Subtract 9 from each side

k+9-9 = -12-9

k = -21

Nuetrik [128]3 years ago
7 0

Answer:

\huge\boxed{k=21}

Step-by-step explanation:

\dfrac{9}{2k-3}=\dfrac{4}{k+1}

First step:

Find domain.

We know: the denominator must be different than 0.

Therefore we have:

2k-3\neq0\ \wedge\ k+1

2k-3\neq0\qquad\text{add 3 to both sides}\\2k\neq3\qquad\text{divide both sides by 2}\\\boxed{k\neq1.5}\\\\k+1\neq0\qquad\text{subtract 1 from both sides}\\\boxed{k\neq-1}\\\\\text{Domain:}\ x\in\mathbb{R}\backslash\{-1;\ 1.5\}

Second step:

Solve for k.

\dfrac{9}{2k-3}=\dfrac{4}{k+1}\qquad\text{cross multiply}\\\\9(k+1)=4(2k-3)\qquad\text{use the distributive property}:\ a(b+c)=ab+ac\\\\(9)(k)+(9)(1)=(4)(2k)-(4)(3)\\\\9k+9=8k-12\qquad\text{subtract 9 from both sides}\\\\9k=8k-21\qquad\text{subtract}\ 8k\ \text{from both sides}\\\\\boxed{k=21}\in\text{Domain}

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      The ordered pair to describe A'A' should be (5, 6).

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3 years ago
A data set that consists of many values can be summarized using the five-number summary. Arrange these five values in order from
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What k-1/3=5/6 equal ?
JulijaS [17]
The value of "K"

k -\frac{1}{3} = \frac{5}{6}

MMC (3,6)
3,6 | 3
1,2 | 2
1,1 |__ 3*2 = 6

Solving:
k -\frac{1}{3} = \frac{5}{6}
\frac{6k}{6} - \frac{2}{6} = \frac{5}{6}
cancel denominators (6)
6k - 2 = 5
6k = 5+2
6k = 7
\boxed{k =  \frac{7}{6} }


7 0
3 years ago
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