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oee [108]
3 years ago
6

What is the justification for step 2 in the solution process?

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

Answer C

Step-by-step explanation:

You are balancing this equation out by <em>subtracting 7x</em> from both sides. This means you are using the subtraction property of equality.

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Which equation represents a line which is parallel to the line 2x+5y=-35? ( see choices )
Bas_tet [7]
I honestly think B but I'm not sure
5 0
3 years ago
¿Cuál dígito debe ir en el recuadro para
Keith_Richards [23]

Answer:

7

Step-by-step explanation:

English:

Which digit should go in the box to

make the next number divisible

between 2, 3 and 9? 8 ,? 48

Let x be the number, then the number will look like this:

8x48

This number is already divisible by 2, because it ends with an even number.

Now we need to check for divsibility by 3.

For this to be divisible by 3, the sum of the digit should be a multiple of 3.

8 + x + 4 + 8 = x +20

We know if a number is divsible by 9, it is also divsible by 3.

So

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The least positive solution is

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x = 7

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4 0
3 years ago
Simplify<br> (3^5)^2/3^-2<br> Answer Options:<br> 3^9<br> 3^8<br> 3^10<br> 3^12
jek_recluse [69]
3^8 that is the answer
3 0
3 years ago
Find the Taylor series for
Basile [38]
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f(x)=\Sigma _{n=0}^{\infty} \,c_{n} (x-\pi)^{n}
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That is 
f(x) = c₀ + c₁(x-π) +c (x-π)² + c₃ (x-π)³ + ...,
 ₂
The first few derivatives of f(x) are
f' = c₁
f'' = 2c₂ = 2! c₂
f''' = 3.2c₃ = 3! c₃
f⁽⁴⁾ = 4.3.2c₄ = 4! c₄
and so on.

The pattern indicates that
c_{n}= \frac{f^{n}(\pi)}{n!}

The derivatives of f(x) are
f' = cos(x)
f'' = -sin(x)
f''' = -cos(x)
f⁽⁴⁾ = sin(x(
and so on

The pattern indicates that
f⁽ⁿ⁾(x) = cos(x), n=1,5,9, ...,
         = -sin(x), n=2,6,10, ...,
         = -cos(x), n=3,7,11, ...,
         = sin(x), n=4,8,12, ...,

The radius of convergence is |x-π|<1 by the ratio test.
     
7 0
4 years ago
let a and b be rational the difference between a and b is sometimes rational always rational or never rational
Paul [167]
<span>The difference between two rational numbers always is a rational number...

Hope it helps !!!

</span>
6 0
3 years ago
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