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3 years ago

5

At Costco, a flat-screen television with a regular price of $1,790 was reduced by $395. Assuming 800 customers purchased the tel

evision, what were the total sales to Costco?
A. $1,116,000 B. $1,160 C. $1,161,000 D. $116,000

1 answer:

Reil [10]3 years ago

8 0

first you would do

$1790 - 395$

next you would do

$x \times 800$

which would then give you answer choice a

You might be interested in

Which graph shows the solution to the system of linear inequalities? x – 4y < 4 y < x + 1 Image for option 1 Image for opt

slava [35]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

$x-4y$ ----> inequality A

solve for y

$-4y$

$4y>x-4$

$y> (x/4)-1$

The solution of the inequality A is the shaded area above the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,-1)$

The x-intercept is the point $(4,0)$

$y< x+1$ ----> inequality B

The solution of the inequality B is the shaded area below the dashed line

The slope of the dashed line is positive

The y-intercept is the point $(0,1)$

The x-intercept is the point $(-1,0)$

Using a graphing tool

The solution of the system of inequalities in the attached figure

7 0

3 years ago

Please help, thank you so much !!

Sliva [168]

Answer: x = 54

Explanation:

180 - 14 = 166

3x + 4 = 166
3x = 162
x = 162/3 = 54

6 0

3 years ago

The problem is in the picture :)

frozen [14]

Answer:

Last option: 4

Step-by-step explanation:

The quadratic equation simplified: $x^2-4x=-\frac{7}{2}$ has the form:

$ax^2+bx=c$

In this case, you can identify that "a", "b" and "c" are:

$a=1\\b=-4\\c=-\frac{7}{2}$

To solve this quadratic equation by completing the square, Carlos should add $(\frac{b}{2})^2$ to both sides of the equation. This is:

$(\frac{-4}{2})^2=(-2)^2=4$

Then:

$x^2-4x+4=-\frac{7}{2}+4$

Therefore you can observe that the number he should add to both sides of the equation is: 4

8 0

3 years ago

priya starts with $50 in her bank account. she then deposited $20 each weeks for 12 weeks. how many weeks does it take her to ha

trasher [3.6K]

Where is the graph ? I don’t see it

7 0

3 years ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

or

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

or

= 0.01153 computers

6 0

3 years ago