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Vikki [24]
2 years ago
15

HELP WITH THIS PROBLEM RIGHT NOW. If you find x first and then y, will the answer be the same or different

Mathematics
2 answers:
Alja [10]2 years ago
5 0

Answer: it will be the same!

kari74 [83]2 years ago
4 0
It would be the same
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Factor the following expression. 36y - 12
Over [174]

Hey there!


36y - 12


FIRST LOOK AT THE GCF (Greatest Common Factor)


36y: 1, 2, 3, 4, 6, 9, 12, 18, 36, and y


12: 1, 2, 3, 4, 6, and 12


GCF: 12


So, 12 would most likely be number before you make your parentheses


12(?y - 1)


The numbers in your original equation both share 3 & -1


So, therefore the factor form of your equation should be: 12(3y - 1)


Answer: 12(3y - 1)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

7 0
2 years ago
Read 2 more answers
USING the Midpoint Formula , POINT A is at (-3,-5) and point M is at (-0.5,0). what are the coordinates of point B
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{-3}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x-3}{2}~~,~~\cfrac{y-5}{2} \right)~~=~~\stackrel{\stackrel{Midpoint}{M}}{(-0.5~,~0)}\implies \begin{cases} \cfrac{x-3}{2}=-0.5\\[1em] x-3=-1\\ \boxed{x= 2}\\ \cline{1-1} \cfrac{y-5}{2}=0\\[1em] y-5=0\\ \boxed{y=5} \end{cases}

7 0
3 years ago
List the next four multiples of the unit fraction 1/5,
svetoff [14.1K]
Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1

Hope this helps..  :)
6 0
3 years ago
Photo attached please help
aniked [119]
C and E that is the answer
4 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. He understands that the lead product has a battery life
alisha [4.7K]

Answer:

a)

The null hypothesis is H_0: \mu \leq 10

The alternative hypothesis is H_1: \mu > 10

b-1) The value of the test statistic is t = 1.86.

b-2) The p-value is of 0.0348.

Step-by-step explanation:

Question a:

Test if the battery life is more than twice of 5 hours:

Twice of 5 hours = 5*2 = 10 hours.

At the null hypothesis, we test if the battery life is of 10 hours or less, than is:

H_0: \mu \leq 10

At the alternative hypothesis, we test if the battery life is of more than 10 hours, that is:

H_1: \mu > 10

b-1. Calculate the value of the test statistic.

The test statistic is:

We have the standard deviation for the sample, so the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

10 is tested at the null hypothesis:

This means that \mu = 10

In order to test the claim, a researcher samples 45 units of the new phone and finds that the sample battery life averages 10.5 hours with a sample standard deviation of 1.8 hours.

This means that n = 45, X = 10.5, s = 1.8

Then

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.5 - 10}{\frac{1.8}{\sqrt{45}}}

t = 1.86

The value of the test statistic is t = 1.86.

b-2. Find the p-value.

Testing if the mean is more than a value, so a right-tailed test.

Sample of 45, so 45 - 1 = 44 degrees of freedom.

Test statistic t = 1.86.

Using a t-distribution calculator, the p-value is of 0.0348.

5 0
2 years ago
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