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mylen [45]
3 years ago
10

Please help I don’t think I remember this

Mathematics
2 answers:
zalisa [80]3 years ago
6 0
9x10 10x4 here ya goo
nikdorinn [45]3 years ago
4 0

Answer:

im not sure if this is right

Step-by-step explanation:

demension 1: 9 X 10      demension 2: 10 x 4

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Find the difference: 3 4/6 - 1/6
NeTakaya

Answer:

7/2  but as a mixed number 3 1/2

Step-by-step explanation:

8 0
3 years ago
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Identify the solution(s) of the system of equations, if any.<br> -2x - 2y = 4<br> 8y = -8x - 16
liubo4ka [24]
<span>-2x - 2y = 4|:(-2) 8y = -8x - 16|:(-8) 
x+y=-2 -y=x+2 x+y=-2x+y=-2 
</span>Ansfwer  :  x-2 y -2
4 0
3 years ago
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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
At the local market, Bill buys 3 juice boxes and 2 hot dogs at a cost of $8, while Sarah buys 2 juice boxes and 1 hot dog at a c
baherus [9]

Answer:

The cost of each juice boxes is $ 2

The cost of each hot dogs is $ 1  .

Step-by-step explanation:

Given as :

The amount which Bill pays for 3 juice boxes and 2 hot dogs = $ 8

The amount which Sarah pays for 2 juice boxes and 1 hot dogs = $ 5

Let The cost of each juice boxes = $ j

And The cost of each hot dogs = $ h

Now, According to question

3 j + 2 h = 8               .........A

2 j + 1 h = 5                 ..........B

Now, solving the equations

2 × (  2 j + 1 h ) = 2 × 5

or, 4 j + 2 h = 10

I.e ( 4 j + 2 h ) - ( 3 j + 2 h ) = 10 - 8

Or, ( 4 j - 3 j ) + ( 2 j - 2 h ) = 2

Or, j + 0 = 2

∴  j = 2

So , The cost of each juice boxes = j = $ 2

Now, Put the value of j in Eq A

I.e  3 × 2 + 2 h = 8

Or, 6 + 2 h = 8

Or. 2 h = 8 - 6

or, 2 h = 2

∴   h = \frac{2}{2} = 1

So, The cost of each hot dogs = h = $ 1

Hence The cost of each juice boxes is $ 2

And The cost of each hot dogs is $ 1  . Answer

4 0
3 years ago
How do You supposed to do this i need many method to do it.
defon
I like the substitution method. Which is when you make one equation equal only x or y and plug it into the other equation)

There is also the graphing method. If you graphed it, it might not be quite as accurate (at least on hand, on computer you would be pretty exact)

Then there is the elimination method. You multiply one of the equations by a coefficient so that you can eliminate x or y from the equation. 
4 0
3 years ago
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