To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
Since, the number w and 0.8 are additive inverses.
A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".
Since, 'w' and '0.8' are additive inverses of each other such that 
Therefore, the value of 'w' should be '-0.8' so that
.
So, the value of 'w' is =0.8
Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.
Sum of 0.8 and w = 0.8 + w
= 0.8 +(-0.8)
= 0.
Answer:
The line segment 7 cm long is shown below.
Step-by-step explanation:
First we draw a line line segment whose length is 7 cm long. Then we divide the line in small parts.
The length of each part is 1 cm.
Six points on the line segment divides the line in 7 equal parts and length of each part is 1 cm.
From the figure it is noticed that we have total 7 small parts and length of each part is 1 cm. So length of 7 parts is

Hence the total length of line is 7 cm.
Answer:
B=![\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%261%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's do the multiplication AB.
If A=![\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then the first row of A is= (1 0) by the first column of B= (0 0) is equal to zero.
the first row of A is= (1 0) by the second column of B= (0 1) is equal to zero too because 1.0+0.1=0.
the second row of A is= (0 0) by any colum of B is equal to zero too.
So we have found an example that works!